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๊ฐœ๋ฐœ์ž์ทจ๐ŸŒฑ

๐Ÿ“๋ฌธ์ œ ํ’€์ด/๐ŸงฉProgrammers

[Python] ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค ๋‹จ์–ด ๋ณ€ํ™˜ | BFS

2023. 6. 26. 22:04

 

~๋ชฉ์ฐจ~

๋ฌธ์ œ

๋ฌธ์ œ ํ•ด๊ฒฐ ํฌ์ธํŠธ

์ž‘์„ฑ ์ฝ”๋“œ


 

๋ฌธ์ œ

https://school.programmers.co.kr/learn/courses/30/lessons/43163

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

์ฝ”๋“œ ์ค‘์‹ฌ์˜ ๊ฐœ๋ฐœ์ž ์ฑ„์šฉ. ์Šคํƒ ๊ธฐ๋ฐ˜์˜ ํฌ์ง€์…˜ ๋งค์นญ. ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค์˜ ๊ฐœ๋ฐœ์ž ๋งž์ถคํ˜• ํ”„๋กœํ•„์„ ๋“ฑ๋กํ•˜๊ณ , ๋‚˜์™€ ๊ธฐ์ˆ  ๊ถํ•ฉ์ด ์ž˜ ๋งž๋Š” ๊ธฐ์—…๋“ค์„ ๋งค์นญ ๋ฐ›์œผ์„ธ์š”.

programmers.co.kr

 

์ž‘์„ฑ ์ฝ”๋“œ

from collections import deque


def solution(begin, target, words):
    if target not in words:
        return 0
    wordlen = len(begin)

    def diff1(w1, w2):  # ๋‘ ๋‹จ์–ด๊ฐ€ ์•ŒํŒŒ๋ฒณ ํ•˜๋‚˜๋งŒ ๋‹ค๋ฅธ์ง€ ํŒ๋ณ„ํ•˜๋Š” ํ•จ์ˆ˜
        cnt = 0
        for i in range(wordlen):
            if w1[i] != w2[i]:
                cnt += 1
        return True if cnt == 1 else False

    que = deque()
    que.append((begin, 0))  # ์ดˆ๊ธฐ๊ฐ’ ์‚ฝ์ž…
    
    while que:  # BFS
        word, cnt = que.popleft()
        if word == target:  # ์ฐพ๋Š” ๋ฌธ์ž๋ฅผ ์ฐพ์œผ๋ฉด return
            return cnt
        for word2 in words:  # words์˜ ๋ชจ๋“  ๋‹จ์–ด ์ค‘
            if diff1(word, word2):  # ํ์˜ ๊ฐ€์žฅ ์•ž ๋ฌธ์ž์™€ ๊ฐ™์€ ๋‹จ์–ด๊ฐ€ ์žˆ๋‹ค๋ฉด ํ์— ์‚ฝ์ž…
                que.append((word2, cnt + 1))
    return 0

 

 

 

๋„์›€์ด ๋˜์…จ๋‹ค๋ฉด ์ข‹์•„์š” ๋ˆŒ๋Ÿฌ์ฃผ์„ธ์š”๐Ÿ’š

 

 

 

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